Optimal. Leaf size=112 \[ -\frac {2 \sqrt {1+a^2 x^2}}{5 a \sinh ^{-1}(a x)^{5/2}}-\frac {4 x}{15 \sinh ^{-1}(a x)^{3/2}}-\frac {8 \sqrt {1+a^2 x^2}}{15 a \sqrt {\sinh ^{-1}(a x)}}-\frac {4 \sqrt {\pi } \text {Erf}\left (\sqrt {\sinh ^{-1}(a x)}\right )}{15 a}+\frac {4 \sqrt {\pi } \text {Erfi}\left (\sqrt {\sinh ^{-1}(a x)}\right )}{15 a} \]
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Rubi [A]
time = 0.14, antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps
used = 9, number of rules used = 7, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.875, Rules used = {5773, 5818,
5819, 3389, 2211, 2235, 2236} \begin {gather*} -\frac {8 \sqrt {a^2 x^2+1}}{15 a \sqrt {\sinh ^{-1}(a x)}}-\frac {2 \sqrt {a^2 x^2+1}}{5 a \sinh ^{-1}(a x)^{5/2}}-\frac {4 \sqrt {\pi } \text {Erf}\left (\sqrt {\sinh ^{-1}(a x)}\right )}{15 a}+\frac {4 \sqrt {\pi } \text {Erfi}\left (\sqrt {\sinh ^{-1}(a x)}\right )}{15 a}-\frac {4 x}{15 \sinh ^{-1}(a x)^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 2211
Rule 2235
Rule 2236
Rule 3389
Rule 5773
Rule 5818
Rule 5819
Rubi steps
\begin {align*} \int \frac {1}{\sinh ^{-1}(a x)^{7/2}} \, dx &=-\frac {2 \sqrt {1+a^2 x^2}}{5 a \sinh ^{-1}(a x)^{5/2}}+\frac {1}{5} (2 a) \int \frac {x}{\sqrt {1+a^2 x^2} \sinh ^{-1}(a x)^{5/2}} \, dx\\ &=-\frac {2 \sqrt {1+a^2 x^2}}{5 a \sinh ^{-1}(a x)^{5/2}}-\frac {4 x}{15 \sinh ^{-1}(a x)^{3/2}}+\frac {4}{15} \int \frac {1}{\sinh ^{-1}(a x)^{3/2}} \, dx\\ &=-\frac {2 \sqrt {1+a^2 x^2}}{5 a \sinh ^{-1}(a x)^{5/2}}-\frac {4 x}{15 \sinh ^{-1}(a x)^{3/2}}-\frac {8 \sqrt {1+a^2 x^2}}{15 a \sqrt {\sinh ^{-1}(a x)}}+\frac {1}{15} (8 a) \int \frac {x}{\sqrt {1+a^2 x^2} \sqrt {\sinh ^{-1}(a x)}} \, dx\\ &=-\frac {2 \sqrt {1+a^2 x^2}}{5 a \sinh ^{-1}(a x)^{5/2}}-\frac {4 x}{15 \sinh ^{-1}(a x)^{3/2}}-\frac {8 \sqrt {1+a^2 x^2}}{15 a \sqrt {\sinh ^{-1}(a x)}}+\frac {8 \text {Subst}\left (\int \frac {\sinh (x)}{\sqrt {x}} \, dx,x,\sinh ^{-1}(a x)\right )}{15 a}\\ &=-\frac {2 \sqrt {1+a^2 x^2}}{5 a \sinh ^{-1}(a x)^{5/2}}-\frac {4 x}{15 \sinh ^{-1}(a x)^{3/2}}-\frac {8 \sqrt {1+a^2 x^2}}{15 a \sqrt {\sinh ^{-1}(a x)}}-\frac {4 \text {Subst}\left (\int \frac {e^{-x}}{\sqrt {x}} \, dx,x,\sinh ^{-1}(a x)\right )}{15 a}+\frac {4 \text {Subst}\left (\int \frac {e^x}{\sqrt {x}} \, dx,x,\sinh ^{-1}(a x)\right )}{15 a}\\ &=-\frac {2 \sqrt {1+a^2 x^2}}{5 a \sinh ^{-1}(a x)^{5/2}}-\frac {4 x}{15 \sinh ^{-1}(a x)^{3/2}}-\frac {8 \sqrt {1+a^2 x^2}}{15 a \sqrt {\sinh ^{-1}(a x)}}-\frac {8 \text {Subst}\left (\int e^{-x^2} \, dx,x,\sqrt {\sinh ^{-1}(a x)}\right )}{15 a}+\frac {8 \text {Subst}\left (\int e^{x^2} \, dx,x,\sqrt {\sinh ^{-1}(a x)}\right )}{15 a}\\ &=-\frac {2 \sqrt {1+a^2 x^2}}{5 a \sinh ^{-1}(a x)^{5/2}}-\frac {4 x}{15 \sinh ^{-1}(a x)^{3/2}}-\frac {8 \sqrt {1+a^2 x^2}}{15 a \sqrt {\sinh ^{-1}(a x)}}-\frac {4 \sqrt {\pi } \text {erf}\left (\sqrt {\sinh ^{-1}(a x)}\right )}{15 a}+\frac {4 \sqrt {\pi } \text {erfi}\left (\sqrt {\sinh ^{-1}(a x)}\right )}{15 a}\\ \end {align*}
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Mathematica [A]
time = 0.13, size = 111, normalized size = 0.99 \begin {gather*} \frac {-2 e^{\sinh ^{-1}(a x)} \left (3+2 \sinh ^{-1}(a x)+4 \sinh ^{-1}(a x)^2\right )+8 \left (-\sinh ^{-1}(a x)\right )^{5/2} \Gamma \left (\frac {1}{2},-\sinh ^{-1}(a x)\right )+e^{-\sinh ^{-1}(a x)} \left (-6+4 \sinh ^{-1}(a x)-8 \sinh ^{-1}(a x)^2+8 e^{\sinh ^{-1}(a x)} \sinh ^{-1}(a x)^{5/2} \Gamma \left (\frac {1}{2},\sinh ^{-1}(a x)\right )\right )}{30 a \sinh ^{-1}(a x)^{5/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 2.73, size = 105, normalized size = 0.94
method | result | size |
default | \(-\frac {2 \left (2 \arcsinh \left (a x \right )^{3} \pi \erf \left (\sqrt {\arcsinh \left (a x \right )}\right )-2 \arcsinh \left (a x \right )^{3} \pi \erfi \left (\sqrt {\arcsinh \left (a x \right )}\right )+4 \arcsinh \left (a x \right )^{\frac {5}{2}} \sqrt {a^{2} x^{2}+1}\, \sqrt {\pi }+2 \arcsinh \left (a x \right )^{\frac {3}{2}} \sqrt {\pi }\, a x +3 \sqrt {\arcsinh \left (a x \right )}\, \sqrt {\pi }\, \sqrt {a^{2} x^{2}+1}\right )}{15 \sqrt {\pi }\, a \arcsinh \left (a x \right )^{3}}\) | \(105\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\operatorname {asinh}^{\frac {7}{2}}{\left (a x \right )}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {1}{{\mathrm {asinh}\left (a\,x\right )}^{7/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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